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# Utility rate per kilowatt hour

1.  Junior Member
Join Date
Jun 2017
Posts
4
Reputation ## Utility rate per kilowatt hour

The electric utility provider charges 15.088 cents per kilowatt hour of electricity. In a month a customer uses 236 kilowatt hours of electricity, how much is the customer charged?

\$356.08

\$35.61

\$3.56

\$0.36

\$0.04

unless i am doing the math wrong (236 / 0.15088) = 1,564.156  Reply With Quote

2.  Member
Join Date
Dec 2015
Posts
38
Reputation  Originally Posted by rmr660 The electric utility provider charges 15.088 cents per kilowatt hour of electricity. In a month a customer uses 236 kilowatt hours of electricity, how much is the customer charged?

\$356.08

\$35.61

\$3.56

\$0.36

\$0.04

unless i am doing the math wrong (236 / 0.15088) = 1,564.156
0.15088 x 236 = 35.60768  Reply With Quote

3.  Junior Member
Join Date
Jul 2020
Posts
3
Reputation ## Try keeping all units when doing math Originally Posted by Sanjayo 0.15088 x 236 = 35.60768
I try and keep all units when doing math so I don't divide when I should multiply and vice versa. For this example;

\$0.15088/kW-Hr * 236 kW-Hr = \$35.61

You can see that the "kW-Hr" in the \$0.15088/kW-Hr cancels the "kW-Hr" in the 236 kW-Hr so all you are left with is \$. If you divide, the "kW-Hr" becomes squared and the answer is \$1,564.16/kW-Hr^2 which does not make any sense.  Reply With Quote

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