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What KVAR is needed to get at PF of .95?

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  1. cbrazzil is offline Junior Member Pro Subscriber
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    What KVAR is needed to get at PF of .95?

    Given 750KVA and a PF of .75, what KVAR is needed to get at PF of .95?

    Unknowns= KW and KVAR1 and KVAR2
    First solve for Ø
    PF=COSØ Ø=41.4
    Next solve for W
    COSØ=W/VA 750,000*COS(41.4)=562500 Watts or 562.5KW
    We don't need to solve for the KVAR1

    New system of PF of .95
    Solve for Ø=18.2
    Next solve for VAR
    TANØ=VAR/W 562500*TAN(18.2)= 184940.59 185=KVAR is the needed KVAR

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