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CT Apparent Burden Problem

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  1. dukeofsmooth's Avatar
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    CT Apparent Burden Problem

    A watt-hour meter draws 1.5 watts and 11.3 Vars from a potential transformer, and 1.88 watts and 1.8 Vars from a current transformer, the total apparent burden placed on the current transformer is?

    Explain the concept of this "apparent burden" problem.
    *Give me a smart idiot over a stupid genius any day*

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    Quote Originally Posted by dukeofsmooth View Post
    A watt-hour meter draws 1.5 watts and 11.3 Vars from a potential transformer, and 1.88 watts and 1.8 Vars from a current transformer, the total apparent burden placed on the current transformer is?

    Explain the concept of this "apparent burden" problem.
    Burden is shown as apparent power (S or VA). Thus to calculate the total apparent burden placed on just the CT, we need to convert watts and vars to VA.
    S^2=P^2+Q^2
    S=sqrt((1.88 Watts)^2+(1.8 Vars)^2) = 2.603 VA

    That's my best guess at the answer, seems to simple to be right though.

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    Quote Originally Posted by Kalbi_Rob View Post
    Burden is shown as apparent power (S or VA). Thus to calculate the total apparent burden placed on just the CT, we need to convert watts and vars to VA.
    S^2=P^2+Q^2
    S=sqrt((1.88 Watts)^2+(1.8 Vars)^2) = 2.603 VA

    That's my best guess at the answer, seems to simple to be right though.
    You used the "Power Triangle" in concert with the Pythagorean theorem to solve! Great stuff! I did not see or thinkof that for whatever.
    *Give me a smart idiot over a stupid genius any day*

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