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    Transformer Math Questions

    Received a Pair of similar questions involving current calculations on Transformers, but I'm having trouble figuring out their math.

    A primary injection is to be performed on a transformer rated 138kV/25kV, 2500kVA, 8%Z using a 480V generator connected to the high side with the low side grounded. What is the expected current on the high side?

    a) 18.116A
    b) 12.5A
    c) 226.45A
    d) 0.787A
    e) 1.36A

    And:

    A primary injection is to be performed on a D-Y transformer rated 138kV/25kV, 2500kva, 8%Z using a 480V generator connected to the high side with the low side grounded. What is the expected current on the high side?


    a) 0.262A
    b) 0.455A
    c) 0.787A
    d) 1.36A

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    Quote Originally Posted by david.hatch View Post
    Received a Pair of similar questions involving current calculations on Transformers, but I'm having trouble figuring out their math.

    A primary injection is to be performed on a transformer rated 138kV/25kV, 2500kVA, 8%Z using a 480V generator connected to the high side with the low side grounded. What is the expected current on the high side?

    a) 18.116A
    b) 12.5A
    c) 226.45A
    d) 0.787A
    e) 1.36A

    And:

    A primary injection is to be performed on a D-Y transformer rated 138kV/25kV, 2500kva, 8%Z using a 480V generator connected to the high side with the low side grounded. What is the expected current on the high side?


    a) 0.262A
    b) 0.455A
    c) 0.787A
    d) 1.36A
    For the first one:

    1. Divide kVA by primary voltage to find FLA

    2,500,000/138,000 = 18.11

    2. Divide FLA by impedance to find short circuit current

    18.11/(.08) = 226.44 A

    3. Calculate ratio for 480V and multiply by short circuit current

    226.44 A * (480/138000) = .787 A


    For the second one, just use three phase voltage in the FLA calculation:

    2500kVA/(sqrt(3)*138kV) = 10.45924 A

    10.45924/(.08) = 130.7405 A

    130.7405 A * (480/138000) = .4548 A

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    Quote Originally Posted by SecondGen View Post
    For the first one:

    1. Divide kVA by primary voltage to find FLA

    2,500,000/138,000 = 18.11

    2. Divide FLA by impedance to find short circuit current

    18.11/(.08) = 226.44 A

    3. Calculate ratio for 480V and multiply by short circuit current

    226.44 A * (480/138000) = .787 A


    For the second one, just use three phase voltage in the FLA calculation:

    2500kVA/(sqrt(3)*138kV) = 10.45924 A

    10.45924/(.08) = 130.7405 A

    130.7405 A * (480/138000) = .4548 A
    Ok, that just confused me. Is the reasoning for the different calculations based on an assumption that the first question is single phase xfmr, while the second one specifically calls out D-Y?
    I thought FLA calculation was independent of single phase or three phase with FLA=(KVA*1000)/(Sqrt(3)*V(L-L)). Which as I type this would answer my confusion as long as the assumption is the first XFMR is single phase.

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    Quote Originally Posted by Kalbi_Rob View Post
    Ok, that just confused me. Is the reasoning for the different calculations based on an assumption that the first question is single phase xfmr, while the second one specifically calls out D-Y?
    I thought FLA calculation was independent of single phase or three phase with FLA=(KVA*1000)/(Sqrt(3)*V(L-L)). Which as I type this would answer my confusion as long as the assumption is the first XFMR is single phase.
    Sorry, I was assuming first transformer is single phase. Second is assumed to be 3-phase because of the D-Y. That is the only difference I see in the two questions.

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    Quote Originally Posted by SecondGen View Post
    Sorry, I was assuming first transformer is single phase. Second is assumed to be 3-phase because of the D-Y. That is the only difference I see in the two questions.
    I agree with the assumption of the single phase transformer, no 1.732 in calculation. If that was not the case then the two questions would have the same answer.

    That is very tricky that they would ask those two questions on the same test worded almost identically?

    You also have to pay attention to the fact that they are asking for the primary Isc and not the secondary.

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