
Originally Posted by
SecondGen
Step 1: Calculate the needed Voltage Drop by subtracting the 2 voltages
125V  24V = 101V
Step 2: Calculate the needed Resistance using ohms law: R = V / I
101V / 0.500 = 202 Ohms
Step 3: Calculate Resistor Wattage from the Current and Resistance using P = I2R
0.500 x 0.500 x 202 = 50.5W
is that means that two resistors connected in series?

Originally Posted by
jwdrowe
An ATS does not transfer from utility to generator. The generator is running and producing voltage. Which of the following is the cause of it not transferring?
A) The breaker feeding the ATS did not open
B) battery does not have enough charge to operate the ATS
C) Frequency of the generator is too low
D) Service only lost one phase
I just completed the Exam today and this question was on it. However, it had more to the scenario. Something to the effect of the utility power was lost at the start. This to me helped me to rule out D which implies the power was not completely lost. I chose C in the end.

Originally Posted by
jwdrowe
According to the NFPA 70, what is the max allowable time delay results for a ground fault relay to operate?
A) 1 second at 1200 amps
B) 3 sec at 3000 amps
C) 5 sec at 1200 amps
D) At the actual available fault current
i found that the book said 1 sec at 3000+ amps
This one was also on mine and one of the choices was 1 sec at 3000 amps which is exactly what you found. I would like to know what book it was found in??

SF6 Gage measures what?
Originally Posted by
dvansick2345
I would of said density or level but I'm not sure
The answer is Density. I remember this bening a topic of discussion from one of the pop quizzes in the NETA World publications in the last couple years. Its also somewhere in the study guide that NETA has. The one with a combined set of pop quizzes from all past issues.

Originally Posted by
NoWorldOrder
The correct answer is D. All I can think of is that the question is asking about an ATS that is only monitoring one phase. Also to consider, in MTM transfer schemes (which I've written the logic for many times) the endusers do not want a transfer on a single phase going to ground. They want the HRG to handle it and then to let the motors run on two phases while they track it down.
Anyway, the correct answer is D. Had the same question.
I humbly disagree with NoWorldOrder in that the question states that the generator is running and is at voltage. If the system is monitoring a different phase than a 'single phase event', there would be no start command to the genset. I believe the answer is that frequency is not in the transfer band to give the ATS a permissive. IMHO anyways, for what that might be worth.

Originally Posted by
SecondGen
Step 1: Calculate the needed Voltage Drop by subtracting the 2 voltages
125V  24V = 101V
Step 2: Calculate the needed Resistance using ohms law: R = V / I
101V / 0.500 = 202 Ohms
Step 3: Calculate Resistor Wattage from the Current and Resistance using P = I2R
0.500 x 0.500 x 202 = 50.5W
Late to the game response, I know, but you don't even need to calculate the resistance. Do the KVL to figure out voltage drop of 101 volts, then multiply by 500mA since total current flows through both components, and power is as easy as PIE (P=I x E).

Originally Posted by
ElectricalTestTech
Well here is my attempt at helping you. Someone please feel free to correct me if I'm wrong.
1. What is an application for a circuit switcher with a preinsertion inductor?
A) Transient control w/ high fault currents
B) Transient control for capacitor bank switching
C) Current damping at 12.4kV
D) Current damping above 34.5kV
A preinsertion inductor arrangement is provided for a circuit switcher to reduce audible and electrical noise and to limit transient inrush current and/or voltages upon closing of the circuit by the circuit switcher. Preinsertion inductors have been introduced as a costeffective alternative to preinsertion resistors for controlling capacitor bank energization overvoltages.
I have to go with B
2. How is lagging power factor improved using a synchronous motor?
A) Raise excitation of field windings
B) Lower excitation of field windings
C) Raise excitation of amortisseur winding
D) Lower excitation of amortisseur winding
A Synchronous Motor can be made to operate at unity and leading power factor by just increasing its excitation voltage by increasing the field current. I believe the answer is A. But someone please chime in on this one
In the old days the utility used synchronous motors to control reactive power. They would not drive a load. By control of the excitation current they could offset and bring the power factor close to unity.
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