
Resistor Circuit Practice Questions
Two 1.2 k resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is
A. 138
B. 1,389
C. 5,700
D. 880

Resistor Circuits
Two 3.3 k resistors are in series and this series combination is in parallel with a 4.7 k resistor. The voltage across one of the 3.3 k resistors is 12 V. The voltage across the 4.7 k resistor is
A. 24 V
B. 12 V
C. 0 V
D. 6 V

Originally Posted by
Vysakh9292
Two 1.2 k resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is
A. 138
B. 1,389
C. 5,700
D. 880
b. 1.389

Originally Posted by
Vysakh9292
Two 1.2 k resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is
A. 138
B. 1,389
C. 5,700
D. 880
Series:R1 +R2 = 2.4 *10 ^3
Parallel: Rt Series * R3/ Rt Series + R3 = 1.389 * 10 ^3
Rt Parallel = 1.389 * 10 ^3

Originally Posted by
Vysakh9292
Two 1.2 k resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is
A. 138
B. 1,389
C. 5,700
D. 880
Rseries=1200 + 1200 = 2400
Rtotal = (2400*3300)/(2400+3300) = 1389 ohms or 1.389 k
https://makeabilitylab.github.io/phy...parallel.html
Originally Posted by
Vysakh9292
Two 3.3 k resistors are in series and this series combination is in parallel with a 4.7 k resistor. The voltage across one of the 3.3 k resistors is 12 V. The voltage across the 4.7 k resistor is
A. 24 V
B. 12 V
C. 0 V
D. 6 V
Since one 3.3k resistor is half the circuit of the 2 3.3k resistors in series, then the total voltage drop across both 3.3k ohm resistors is now 12*2 = 24V. Since 2 3.3k ohm resistors are in parallel with a 4.7k ohm resistor, and voltage is equal across parallel paths, then the voltage across the 4.7k ohm resistor is also 24V.

Originally Posted by
Vysakh9292
Two 1.2 k resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is
A. 138
B. 1,389
C. 5,700
D. 880
1.389k Ohms

Originally Posted by
Vysakh9292
Two 1.2 k resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is
A. 138
B. 1,389
C. 5,700
D. 880
5700
2400x3300/2400+3300=
7920000./5700.=1389
1/2.4+1/3.3= .7196
1/7196=1.389
Last edited by edgarenc; July 16, 2022 at 11:38 AM.
Reason: was wrong

Originally Posted by
Vysakh9292
Two 1.2 k resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is
A. 138
B. 1,389
C. 5,700
D. 880
The answer is B.
The absolute best way to make this calculation is, (1/2.4+1/3.3)^1 = 1.38947 in kOhms that is 1,389 ohms
resistors in series ADD
resistors in parallel inversely add.........................^^^^^^^^^......hence the whole equation to the ^1
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