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Neta 3 Exam questions

    #11
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    Quote Originally Posted by cjones09 View Post
    Also not sure how to solve this, somehow need to find real power first. Where does the 45 magnitude come in?

    Can anyone help provide a solution?
    Q=VxI Sin ɸ

    Polar coordinates(r,θ) -----------------> Rectangular Coordinates ( r Sin θ, r Cos θ)
    θ=10º ( 45 Sin 10º, 45 Cos 10º ) ===> ( 7.814167995, 44.31634889 )
    r=45 ( x , y ) ===> ( x , y )
    Tan θ = y/x
    θ= Tan^-1 (y/x) = Tan ^-1 (44.31634889 / 7.814167995) = 80º

    plug in all values

    Q = 120 x 10 x Sin 80º = 1181.769304 VAR.

    Even though none of the answers match i think this is the right answer.!!
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  2. #12
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    Quote Originally Posted by Zepold72 View Post
    Q=VxI Sin ɸ

    Polar coordinates(r,θ) -----------------> Rectangular Coordinates ( r Sin θ, r Cos θ)
    θ=10º ( 45 Sin 10º, 45 Cos 10º ) ===> ( 7.814167995, 44.31634889 )
    r=45 ( x , y ) ===> ( x , y )
    Tan θ = y/x
    θ= Tan^-1 (y/x) = Tan ^-1 (44.31634889 / 7.814167995) = 80º

    plug in all values

    Q = 120 x 10 x Sin 80º = 1181.769304 VAR.

    Even though none of the answers match i think this is the right answer.!!
    The number you calculated is KVA not KVAR. Use the pyragorean theorem. Kva^2 = kw^2 + kvar^2. The mag*sine (theta) ×amps is the kvar = reactive power and not the apparent power in which you calculated. ( Those who read this, look up the power triangle and decide for yourselves)
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  4. #13
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    Nov 2015
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    Thanks rsimmons!! I realized it after I posted that I solved for the wrong power.
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  6. #14
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    Apr 2015
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    so did you pass??
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  8. #15
  9. Join Date
    Nov 2016
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    I'm having problems taking exams on my phone and iPad can someone help
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