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  • Vernon's Avatar
    4 Days Ago
    I guess you want to come up with all three values for both feeders to get all parameters of the load. In the case of the first load 1200KW at .8 - 1200/.8 = 1500KVA. The angle is 36.869 degrees so you have (sine) 900KVAR. Load 1 is fully described as 1500KVA, 1200KW, and 900KVAR. Load 2 at 800KVA and 300KVAR. The angle is ARC SIN 300/800 = 22.02...
    5 replies | 5292 view(s)
  • Vernon's Avatar
    5 Days Ago
    It would seem that the CTs would be connected in parallel, polarity marking connected together - parallel additive. If you had 200 A on feeder 1, that CT would source 2.5 Amps. If you had 200A on feeder 2, you also get 2.5 A from that CT. 400A total gives you 5 A so the relay should be set to 400:5. Answer A is close but there is no correct answer. It...
    5 replies | 1246 view(s)
  • Vernon's Avatar
    6 Days Ago
    The connection may have resulted in stray current flowing through the CT.
    2 replies | 504 view(s)
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